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There are two sets of letters, and you are going to pick exactly one letter from each set.
Set #1 = {A, B, C, D, E}
Set #2 = {K, L, M, N, O, P}
What is the probability of picking a C and an M?
  • a)
    1/30
  • b)
    1/15
  • c)
    1/6
  • d)
    1/5
  • e)
    1/3
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
There are two sets of letters, and you are going to pick exactly one l...
Whatever we pick from the first set is independent with whatever we pick from the second set, so we can use the simplified AND rule.
P(first pick = C) = 1/5
P(second pick = M) = 1/6
P(C and M) = P(C)*P(M) = (1/5)*(1/6) = 1/30
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Community Answer
There are two sets of letters, and you are going to pick exactly one l...
Calculation of Probability
To calculate the probability of picking a C and an M, we need to first determine the total number of possible outcomes. There are 5 options in Set #1 and 6 options in Set #2, so the total number of possible outcomes is 5 x 6 = 30.

Number of Desired Outcomes
There is only one C in Set #1 and one M in Set #2. Therefore, the number of desired outcomes is 1 x 1 = 1.

Probability Calculation
To calculate the probability, we divide the number of desired outcomes by the total number of possible outcomes:
Probability = Number of Desired Outcomes / Total Number of Possible Outcomes
Probability = 1 / 30
Probability = 1/30
Therefore, the probability of picking a C and an M is 1/30, which corresponds to option 'A'.
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